Math.random（）返回0（含）和1（独占）之间的随机数，有一点技巧，你可以有

Math.random() returns a random number between 0 (inclusive) and 1 (exclusive), with a bit of trick, you can have

Math.random()*12+1

将返回1（含）和13（独家）之间的随机数。

这样，那里无需检查是否出现0.

由于您重复使用相同的代码生成多个随机数，因此请将此代码放在函数中以便更好地重复使用代码，例如

that will return a random number between 1 (inclusive) and 13 (exclusive).
In this way, there is no need to check for the occurrence of 0.
Since you are re-using the same code to generate multiple random numbers, put this code in a function for better code re-use, e.g.

function getRndNumb(){
  return Math.floor(Math.random()*12+1);
}

最后，要在重复时重复生成随机数，请使用循环，在这种情况下执行...虽然更合适，例如

Lastly, to repeatedly re-generate random numbers when there is duplication, use a loop, in this case do...while is more appropriate, e.g.

do {
   numb1 = getRndNumb();
   numb2 = getRndNumb();
   numb3 = getRndNumb();
} while (numb1 == numb2 || numb1==numb3 || numb2==numb3)

我会留给你把这些作品放在一起。

I shall leave it to you to put together these pieces.

而不是只检查一次数字，在一个循环中检查它们

循环播放JavaScript时[ ^ ]



例如你可以做这样的事情（注意 - 未经测试）

Rather than just checking the numbers once, check them in a while loop
JavaScript while Loop[^]

e.g. you could do something like this (Note - untested)

while (numb1 == numb2 || numb2 == numb3 || numb1 == numb3 || numb1 == 0 || numb2 == 0 || numb3 == 0){
    if(numb1 == 0 || numb1 == numb2 || numb1 == numb3){
        numb1 = numb1 + 1;
    if(numb2 == 0 || numb2 == numb3 || numb2 == numb3){
        numb2 = numb2 + 1;
    if(numb3 == 0 || numb3 == numb1 || numb3 == numb2){
        numb3 = numb3 + 1;
}