关于您关于如何手动执行此操作的问题，我将通过这个简单的代码给您一个想法，它解决了您在问题中给出的示例.

Regarding your question on how to do it manually, i will give you an idea with this simple code, which solves the example which you gave in the question.

#include<iostream>
#include<string>
using namespace std;
int main()
{
    string expr="How is * doing?";
    string input="How is Mom doing?";
    int wildcard_pos=expr.find("*");
    if(wildcard_pos!=string::npos)
    {
        int foo=input.find(expr.substr(0,wildcard_pos)),bar=input.find(expr.substr(wildcard_pos+1));
        if(foo!=string::npos && bar!=string::npos)
        cout<<input.substr(wildcard_pos,bar-wildcard_pos)<<" is doing fine\n";
    }
}

您可以轻松修改此想法以满足您的需求.否则，按照 src

You can easily modify this idea to suit your needs. Else, follow the answer given by src