更新时间:2021-11-25 09:00:09
您不能使用YEAR
函数获取年份差,因为这将在2012年12月31日至2013年1月1日之间给出1年,而只有一天的时间.....
You can't use YEAR
function to get year difference because that will give 1 year between 31st December 2012 and 1st Jan 2013 when there is only one day.....
....同样,您可能会遇到MONTH和DAY的问题(例如MONTH总是返回1到12之间的数字,而在这种情况下,您只会期望0到11之间的数字)
....similarly you can have problems with MONTH and DAY (e.g. MONTH always returns a number between 1 and 12 whereas in this context you would only expect numbers between 0 and 11)
尝试用DATEDIF
表示前3个,然后按贾斯汀的建议HOUR
,MINUTE
,SECOND
Try DATEDIF
for the first 3 then HOUR
, MINUTE
, SECOND
as Justin suggests
假设A2中的开始日期/时间和B2中的结束日期/时间分别尝试使用以下公式分别表示年,月,日,时,分和秒
Assuming start date/time in A2 and end date/time in B2 try these formulas respectively for Years, Months, Days, Hours, Minutes and Seconds
=DATEDIF(A2,B2-(MOD(A2,1)>MOD(B2,1)),"y")
=DATEDIF(A2,B2-(MOD(A2,1)>MOD(B2,1)),"ym")
=DATEDIF(A2,B2-(MOD(A2,1)>MOD(B2,1)),"md")
=HOUR(B2-A2)
=MINUTE(B2-A2)
=SECOND(B2-A2)
将所有单元格设置为常规格式
format all cells as general
由于月份/年份的长短不一,您可能会出现一些差异……
You may get some discrepancies because of variable month/year lengths......