Shapely仅使用笛卡尔坐标系，因此为了了解公制距离，您需要:

Shapely only uses the Cartesian coordinate system, so in order to make sense of metric distances, you would need to either:

1. 将坐标投影到使用米的距离单位(例如UTM区域)的本地投影系统中.
2. 从(0,0)开始缓冲一点，并使用动态的方位角等距投影以纬度/经度点为中心，以投影到地理坐标.

1. project the coordinates into a local projection system that uses distance units in metres, such as a UTM zone.
2. buffer a point from (0,0), and use a dynamic azimuthal equidistant projection centered on the lat/lon point to project to geographic coords.

这是使用 shapely.ops.transform href ="http://toblerity.org/shapely/manual.html#shapely.ops.transform"的方法. a>和 pyproj

import pyproj
from shapely.geometry import Point
from shapely.ops import transform
from functools import partial

WGS84 = pyproj.Proj(init='epsg:4326')

def latlonbuffer(lat, lon, radius_m):
    proj4str = '+proj=aeqd +lat_0=%s +lon_0=%s +x_0=0 +y_0=0' % (lat, lon)
    AEQD = pyproj.Proj(proj4str)
    project = partial(pyproj.transform, AEQD, WGS84)
    return transform(project, Point(0, 0).buffer(radius_m))

A = latlonbuffer(48.180759, 11.518950, 19.0)
B = latlonbuffer(47.180759, 10.518950, 10.0)
print(A.intersects(B))  # False

您的两个缓冲点不相交.但是这些确实可以做到:

Your two buffered points don't intersect. But these do:

A = latlonbuffer(48.180759, 11.518950, 100000.0)
B = latlonbuffer(47.180759, 10.518950, 100000.0)
print(A.intersects(B))  # True

如绘制lon/lat坐标(扭曲圆)所示:

As shown by plotting the lon/lat coords (which distorts the circles):