datetime.time 对象 不支持使用 datetime.timedeltas 的加法.

虽然有一个自然定义，时钟算法.你可以这样计算:

导入日期时间为 dt现在 = dt.datetime.now()delta = dt.timedelta(小时 = 12)t = 现在.time()打印(吨)# 12:39:11.039864打印((dt.datetime.combine(dt.date(1,1,1),t) + delta).time())# 00:39:11.039864

dt.datetime.combine(...) 将 datetime.time t 提升到 datetime.datetime 对象，增量为然后添加，并将结果返回到 datetime.time 对象.

From:

http://docs.python.org/py3k/library/datetime.html#timedelta-objects

A timedelta object represents a duration, the difference between two dates or times.

So why i get error with this:

>>> from datetime import datetime, timedelta, time
>>> datetime.now() + timedelta(hours=12)
datetime.datetime(2012, 9, 17, 6, 24, 9, 635862)
>>> datetime.now().date() + timedelta(hours=12)
datetime.date(2012, 9, 16)

>>> datetime.now().time() + timedelta(hours=12)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'

datetime.time objects do not support addition with datetime.timedeltas.

There is one natural definition though, clock arithmetic. You could compute it like this:

import datetime as dt
now = dt.datetime.now()
delta = dt.timedelta(hours = 12)
t = now.time()
print(t)
# 12:39:11.039864

print((dt.datetime.combine(dt.date(1,1,1),t) + delta).time())
# 00:39:11.039864

dt.datetime.combine(...) lifts the datetime.time t to a datetime.datetime object, the delta is then added, and the result is dropped back down to a datetime.time object.