我已经修改了我作为问题给出的代码，并得到了我真正需要的，

I have modified the code I gave as a question and have got what I needed actually,

def getSheetName(file_name):
    pointSheetObj = []
    import xlrd as xl
    TeamPointWorkbook = xl.open_workbook(file_name)
    pointSheets = TeamPointWorkbook.sheet_names()

    for i in pointSheets:
        pointSheetObj.append(tuple((TeamPointWorkbook.sheet_by_name(i),i)))

所以如果列表(tuple)pointSheetObj 被迭代，我们在tuple 的index 1 处有工作表的名称 在 pointSheetObj 内.

so if the list (of tuple) pointSheetObj is iterated we have name of the sheet at index 1 of the tuple inside the pointSheetObj.

通过这样做，我获得了名称和工作表对象，我可以用它来继续使用其他与工作表相关的方法.

By doing this I have got the name and the worksheet object with which I can carry on with other sheet related methods.