这并不难实现为迭代器:

This wouldn't be hard to implement as an iterator:

IEnumerable<T> CreateItems<T> (int count) where T : new() {
    return CreateItems(count, () => new T());
}

IEnumerable<T> CreateItems<T> (int count, Func<T> creator) {
    for (int i = 0; i < count; i++) {
        yield return creator();
    }
}