分享程序员开发的那些事...
更新时间：2023-12-03 20:27:28
只需在最后制作一个Script标记，然后获取带有label标记的所有元素，然后删除与您想要的for属性相同的元素.这是可能有用的代码-
Just Make a Script tag in the last and get all element with label tag and delete the element which has the same for attribute as you want. Here is the Code that might help -
<html>
<body>
<table class="variations">
<tbody>
<tr>
<td class="label"><label for="pa_1ef722433d607dd9d2b8b7">Ships From</label></td>
</tr>
<tr>
<td class="label"><label for="pa_cb5feb1b7314637725a2e7">Color</label></td>
</tr>
</tbody>
</table>
<script>
var labeltags = document.getElementsByTagName("label");
for (var i=0;i<labeltags.length;i++){
if (labeltags[i].getAttribute("for")=="pa_cb5feb1b7314637725a2e7"){
labeltags[i].remove();
}
}
</script>
</body>
</html>