分享程序员开发的那些事...
更新时间：2022-06-10 23:30:25
我可以看到三种解决方案:
I can see three ways around this:
使用模板字符串，就像它们设计的那样，没有任何format函数:
console.log(`Hello, ${"world"}. This is a ${"test"}`);
// might make more sense with variables:
var p0 = "world", p1 = "test";
console.log(`Hello, ${p0}. This is a ${p1}`);
甚至函数参数用于实际延迟评估:
or even function parameters for actual deferral of the evaluation:
const welcome = (p0, p1) => `Hello, ${p0}. This is a ${p1}`;
console.log(welcome("world", "test"));
不要使用模板字符串，而是使用纯字符串文字:
Don't use a template string, but a plain string literal:
String.prototype.format = function() {
var args = arguments;
return this.replace(/${p(d)}/g, function(match, id) {
return args[id];
});
};
console.log("Hello, ${p0}. This is a ${p1}".format("world", "test"));
使用标记的模板文字.请注意，替换仍将在没有处理程序拦截的情况下进行评估，因此您不能在没有名为 so 的变量的情况下使用像 p0 这样的标识符.如果不同的替换正文语法 提议被接受(更新:不是).
Use a tagged template literal. Notice that the substitutions will still be evaluated without interception by the handler, so you cannot use identifiers like p0 without having a variable named so. This behavior may change if a different substitution body syntax proposal is accepted (Update: it was not).
function formatter(literals, ...substitutions) {
return {
format: function() {
var out = [];
for(var i=0, k=0; i < literals.length; i++) {
out[k++] = literals[i];
out[k++] = arguments[substitutions[i]];
}
out[k] = literals[i];
return out.join("");
}
};
}
console.log(formatter`Hello, ${0}. This is a ${1}`.format("world", "test"));
// Notice the number literals: ^ ^