更新时间:2022-04-18 23:31:36
这可能无法在此沙箱中运行(使用localstore),但我认为如果您尝试过,它应该可以工作.
This probably will not run in this sandbox (use of localstore), but I think it should work if you tried it.
// -------------------------------
// see: http://***.com/questions/2450954/how-to-randomize-shuffle-a-javascript-array
// -------------------------------
function _shuffle (array) {
for (var i = array.length - 1; i > 0; i--) {
var j = Math.floor(Math.random() * (i + 1));
var temp = array[i];
array[i] = array[j];
array[j] = temp;
}
return array;
}
// -------------------------------
// -------------------------------
// Get the next "random" item.
// -------------------------------
var randomItem = (function(allItems){
var _key = "array";
var _currentItems = [];
try {
_currentItems = JSON.parse(localStorage.getItem(_key) || "[]");
} catch (e) {
_currentItems = [];
}
if (!Array.isArray(_currentItems) || _currentItems.length === 0 ) {
console.log("resetting");
_currentItems = _shuffle(allItems.slice());
}
var _selectedItem = _currentItems.pop();
localStorage.setItem(_key, JSON.stringify(_currentItems));
return _selectedItem;
})(["apple", "orange", "banana"]);
// -------------------------------
console.log(randomItem);
一个更裸露的版本[从上面带有_shuffle()]可能只是:
A more bare bones version [ with _shuffle() from above ] might be just:
var nextItem = (function(all){
var _key = "array";
var _current = JSON.parse(localStorage.getItem(_key) || "[]");
if (_current.length === 0) { _current = _shuffle(all.slice()); }
var _selected = _current.pop();
localStorage.setItem(_key, JSON.stringify(_current));
return _selected;
})(["apple", "orange", "banana"]);