假设你有一个的播放器的类，它是这样的：

Say you have a Player class that looks like:

[XmlRoot]
public class Player
{
    [XmlElement]
    public int Level { get; set; }

    [XmlElement]
    public int Health { get; set; }
}

下面是一个完整的往返让你开始：

Here is a complete round-trip to get you started:

XmlSerializer xmls = new XmlSerializer(typeof(Player));

StringWriter sw = new StringWriter();
xmls.Serialize(sw, new Player { Level = 5, Health = 500 });
string xml = sw.ToString();

Player player = xmls.Deserialize(new StringReader(xml)) as Player;

的 XML 的是：

<?xml version="1.0" encoding="utf-16"?>
<Player xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Level>5</Level>
  <Health>500</Health>
</Player>

和你猜的播放的是完全一样的，因为我们序列化的原始对象

And you guess player is exactly the same as the original object we serialized.

如果你想序列化/反序列化的文件，你可以这样做：

If you want to serialize to/deserialize from files you can do something like:

using (var stream = File.OpenWrite("my_player.xml"))
{
    xmls.Serialize(stream, new Player { Level = 5, Health = 500 });
}

Player player = null;
using (var stream = File.OpenRead("my_player.xml"))
{
    player = xmls.Deserialize(stream) as Player;
}

编辑：

如果您想要完全XML告诉你：

IF you want exactly the XML you show:

XmlSerializer xmls = new XmlSerializer(typeof(Player));

XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("", "");
XmlWriterSettings settings = new XmlWriterSettings { OmitXmlDeclaration = true, Indent = true };
using (var stream = File.OpenWrite("my_player.xml"))
{
    using (var xmlWriter = XmlWriter.Create(stream, settings))
    {
        xmls.Serialize(xmlWriter, new Player { Level = 5, Health = 500 }, ns);
    }
}

Player player = null;
using (var stream = File.OpenRead("my_player.xml"))
{
    player = xmls.Deserialize(stream) as Player;
}