而不是在script_a中使用``.我们已经在script_a中重定向了STDOUT和STDERR. 像

Instead of using `` in script_a. We have redirected the STDOUT and STDERR in script_a. Something like

script_a

system("script_b.pl > /var/tmp/out_file 2>&1");

script_b

#! /usr/local/bin/perl

$f_id = fork();

if (! $f_id) {
    exec("sleep 10; echo 'i am child'");
}

if ($f_id) {
    print "i am parent\n";
}

通过这种方式，调用方不必等待exec中的孩子完成.

This way the caller didnot wait for the child in exec to complete.

感谢您的帮助.