在与 -fPIC 编译问题的对象将通过确定全局符号的地址全局偏移表的。会发生什么，虽然当code的一部分，是 -fPIC 和部分不就是一个你的 INT全球 s将会使用该表来确定该地址，而另一部分是不

When you compile with -fPIC the object in question will determine the address of global symbols using the Global Offset Table. What happens though when part of the code is -fPIC and part isn't is that one of your int globals will be using this table to determine the address whilst the other part isn't.

如果你有两个共享对象， -fPIC 联系，但主程序没有，那么你仍然有两个地址 INT全球，一个使用这只是本地的非PIC code。

If you had two shared object linked with -fPIC, but your main program not then you would still have two addresses for int global, one using the global offset table and one which was just local to the non-PIC code.

有一个关于PIC一个真正伟大的讨论VS PIC与非PIC 如果你要进一步阅读。

There's a really great discussion on PIC vs pic vs non PIC if you want to read further.