你可以使用这个，如果它更优雅:

You can use this, if its more elegant:

def scanl(f, base, l):
    for x in l:
        base = f(base, x)
        yield base

像这样使用:

import operator
list(scanl(operator.add, 0, range(1,11)))

Python 3.x 具有 itertools.accumulate(iterable,func= operator.add).它的实现如下.实施可能会给你一些想法:

Python 3.x has itertools.accumulate(iterable, func= operator.add). It is implemented as below. The implementation might give you ideas:

def accumulate(iterable, func=operator.add):
    'Return running totals'
    # accumulate([1,2,3,4,5]) --> 1 3 6 10 15
    # accumulate([1,2,3,4,5], operator.mul) --> 1 2 6 24 120
    it = iter(iterable)
    total = next(it)
    yield total
    for element in it:
        total = func(total, element)
        yield total