更新时间:2022-01-10 22:22:21
请记住,默认情况下,Jackson 从 getter 或 setter(第一个匹配的)确定属性名称.
Remember that Jackson, by default, determines the property name from either the getter or setter (the first that matches).
要反序列化 POJOUserDetails
类型的对象,Jackson 将查找三个属性
To deserialize an object of type POJOUserDetails
, Jackson will look for three properties
public void setFirstName(String firstName) {
public void setLastName(String lastName) {
public void setActive(boolean isActive) {
在 JSON 中.这些基本上是firstName
、lastName
、active
.
in the JSON. These are basically firstName
, lastName
, active
.
你得到以下 JSON
{ "firstName": "Test", "lastName": "1", "isActive": 1 }
因此 firstName
和 lastName
已映射,但您没有名为 isActive
的属性.
So firstName
and lastName
are mapped, but you don't have a property named isActive
.
Jackson 依赖于 Java Bean 命名约定及其访问器(getter)和修改器(setter).对于像
Jackson depends on Java Bean naming conventions with their accessors (getters) and mutators (setters). For a field like
private boolean isActive;
合适的 setter/getter 名称是
the appropriate setter/getter names are
public boolean getIsActive() {
return isActive;
}
public void setIsActive(boolean isActive) {
this.isActive = isActive;
}
所以你有两种可能的解决方案.如上所示更改您的 getter/setter 或使用 @JsonProperty
注释您的字段,以便 Jackson 使用字段名称来确定属性名称
So you have two possible solutions. Change your getter/setter as shown above or annotate your field with @JsonProperty
so that Jackson uses the field name to determine the property name
@JsonProperty
private boolean isActive;