Problem Description
I believe many people are the fans of *** break. How clever Michael is!! In order that the message won’t be found by FBI easily, he usually send code letters to Sara by a paper crane. Hence, the paper crane is Michael in the heart of Sara. Now can you write a program to help Sara encode the letter from Michael easily?
The letter from Michael every time is a string of lowercase letters. You should encode letters as the rules below:
b is ’ ‘, q is ‘,’, t is ‘!’, m is l, i is e, c is a, a is c, e is i, l is m. It is interesting. Are you found that it is just change michael to leahcim?

Input
The input will consist of several cases, one per line.
Each case is a letter from Michael, the letteres won’t exceed 10000.

Output
For each case, output the encode letter one line.

Sample Input
pmicsibforgevibliqbscrct
ebmovibyout

Sample Output
please forgive me, sara!
i love you!

就是输入一行字符串，然后根据b is ‘空格’, q is ‘,’, t is ‘!’, m is l, i is e, c is a, a is c, e is i, l is m.来转换，输出转换之后的字符串！
在这里，我用Map来存储需要转换的字符，然后查找输出。

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main{

    public static void main(String[] args) {
        Map<Character, Character> map = new HashMap<Character, Character>();
        map.put('b', ' ');
        map.put('q', ',');
        map.put('t', '!');
        map.put('m', 'l');
        map.put('i', 'e');
        map.put('c', 'a');
        map.put('a', 'c');
        map.put('e', 'i');
        map.put('l', 'm');
        Scanner sc = new Scanner(System.in);
        while(sc.hasNext()){
            String str=sc.next();
            for(int i=0;i<str.length();i++){
                if(map.get(str.charAt(i))!=null){
                    System.out.print(map.get(str.charAt(i)));
                }else{
                    System.out.print(str.charAt(i));
                }
            }
            System.out.println();
        }
    }
}