更新时间:2022-06-02 22:43:07
使用的ISO( YYYY-MM-DD
)格式,而不是英语的格式,然后只需使用 ksort
功能让他们在正确的顺序。
Use the ISO (yyyy-mm-dd
) format rather than the "english" format, and then just use the ksort
function to get them in the right order.
有没有需要删除的连字符, ksort
会做的字符串键字母数字的比较,以及 YYYY-MM-DD
格式完美的作品以及词法顺序是一样的实际日期顺序。
There's no need to remove the hyphens, ksort
will do an alphanumeric comparison on the string keys, and the yyyy-mm-dd
format works perfectly well as the lexical order is the same as the actual date order.
修改我现在看到你们已经纠正你的问题,表明你实际上得到一个数组的数组,并且sort关键是在子阵列。在这种情况下,你应该使用 uksort
其他地方推荐的,但我会建议你去用自己的编辑和排序基于DB格式化的日期,而不是通过解析人类可读的格式为:
EDIT I see you've now corrected your question to show that you've actually got an array of arrays, and that the sort key is in the sub-arrays. In this case, you should use uksort
as recommended elsewhere, but I would recommend that you go with your own edit and sort based on the DB formatted date, rather than by parsing the human readable format:
function cmp($a, $b)
{
global $array;
return strcmp($array[$a]['db'], $array[$b]['db']);
}
uksort($array, 'cmp');