尝试以下 CSS选择器

b > span.marked

这将返回跨度，所以你可能要做 $ e-> parent（）以获取b元素。

That would return the span though, so you probably have to do $e->parent() to get to the b element.

另请参阅解析HTML的***方法 for SimpleHtmlDom的替代方法

Also see Best Methods to parse HTML for alternatives to SimpleHtmlDom

更新后修改：

您的浏览器将修改DOM 。 如果您查看标记，您将看到没有tbody元素。但是Firebug给你

Your browser will modify the DOM. If you look at your markup, you will see that there is no tbody elements. Yet Firebug gives you

html body div#wrapper table.desc tbody tr td div span.marked'
html body div#wrapper table.desc tbody tr td table.split tbody tr td b'

另外，你的问题不符合查询。你问如何找到< b>，< / b> $包围的

Also, your question does not match the queries. You asked how to find

c $ c> -tags后跟一个< span class =marked>

可以读取，意思是

<b><span class="marked">foo</span></b>

或

<b><element>foo</element></b><span class="marked">foo</span>

首先使用子组合器我已经显示了。第二，使用相邻兄弟组合器

For that first use the child combinator I have shown earlier. For the second, use the adjacent sibling combinator

b + span.marked

获取跨度，然后使用 $ e-> prev_sibling（）返回元素的上一个同级元素（如果未找到则为null）。

to get the span and then use $e->prev_sibling() to return the previous sibling of element (or null if not found).

但是，在您显示的标记中，既没有也没有。只有DIV与SPAN孩子有标记的类

However, in your shown markup, there is neither nor. There is only a DIV with a SPAN child having the marked class

<div style="text-align: center"> <span class="marked">marked</span>

如果这是你想要匹配的，那就是子组合器。当然，你必须将b改为div。

If that is what you want to match, it's the child combinator again. Of course, you have to change the b then to a div.