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leetCode 387. First Unique Character in a String 字符串

更新时间:2022-10-03 13:53:02

387. First Unique Character in a String

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.

Examples:

s = "leetcode"
return 0.

s = "loveleetcode",
return 2.


Note: You may assume the string contain only lowercase letters.


此题比较简单

代码如下:

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class Solution {
public:
    int firstUniqChar(string s) {
        set<char > myset;
        if (s.empty())
        {
            return -1;
        }
        for(int i = 0 ; i < s.size();i++)
        {
            char c = s[i];
            int j;
            if(myset.find(c) != myset.end())
            {
                continue;
            }
            for(j = i + 1; j < s.size();j++)
            {
                if(s[j] == s[i])
                {
                    myset.insert(c);
                    break;
                }
            }
            if(j == s.size() )
            {
                return i;
            }
        }
        return -1;
    }
};



本文转自313119992 51CTO博客,原文链接:http://blog.51cto.com/qiaopeng688/1842229