虽然我同意使用XML / HTML解析器是一个更好的选择，一般情况下，你的场景很容易用正则表达式解决：

  List&lt ;字符串&GT; titles = new ArrayList< String>（）; 
匹配匹配器= Pattern.compile（< title>（。*？）< / title>）。 （matcher.find（））{
 titles.add（matcher.group（1））; 
} 
 

请注意非贪婪算子。*？并使用 matcher.find（）而不是 matcher.matches（） p>

参考：
$ b

• 模式>不情愿的量词


• Matcher.find（）
  

Have string strng = "<title>text1</title><title>text2</title>"; How to get array like

arr[0] = "text1";
arr[1] = "text2";

I try to use this, but in result have, and not array text1</title><title>text2

Pattern pattern = Pattern.compile("<title>(.*)</title>");
Matcher matcher = pattern.matcher(strng);
matcher.matches();

While I agree that using an XML / HTML parser is a better alternative in general, your scenario is simple to solve with regex:

List<String> titles = new ArrayList<String>();
Matcher matcher = Pattern.compile("<title>(.*?)</title>").matcher(strng);
while(matcher.find()){
    titles.add(matcher.group(1));
}

Note the non-greedy operator .*? and use of matcher.find() instead of matcher.matches().

Reference:

• Pattern > Reluctant Quantifiers
• Matcher.find()