s ='areyo uanap ppple'
 incr = 1 
 out =''
 dict = {} 
 s中的x：
如果''在x中：
 incr = 1 
 dict = {} 
 out + =''
 continue; 
如果在dict.keys（）中的x：
 out + = str（dict [x]）
 continue; 

 out + = str（incr）
 dict [x] = incr 
 incr = incr + 1 

打印输出// 12345 12324 11123 
 

What I have:

s='areyo uanap ppple'

What I want:

s='12345 12324 11123'

Should I use dictionary and translate each i in s.split(' ')? or is there a simpler method?

s='areyo uanap ppple'
incr=1
out=''
dict={}
for x in s:
    if ' ' in x:
        incr=1
        dict={}
        out+=' '
        continue;
    if x in dict.keys():
        out+=str(dict[x])
        continue;

    out+=str(incr)
    dict[x]=incr
    incr=incr+1

print out //12345 12324 11123