且构网

分享程序员开发的那些事...
且构网 - 分享程序员编程开发的那些事

测量代码执行时间

更新时间:2022-10-15 15:58:41

更好的方法是使用 Stopwatch,而不是 DateTime 差异.

秒表类 - Microsoft Docs>

提供一组方法和属性,您可以使用它们准确测量经过的时间.

//创建并启动一个秒表实例秒表 秒表 = Stopwatch.StartNew();//替换为您的示例代码:System.Threading.Thread.Sleep(500);秒表.停止();Console.WriteLine(秒表.ElapsedMilliseconds);

I want to know how much time a procedure/function/order takes to finish, for testing purposes.

This is what I did but my method is wrong 'cause if the difference of seconds is 0 can't return the elapsed milliseconds:

Notice the sleep value is 500 ms so elapsed seconds is 0 then it can't return milliseconds.

    Dim Execution_Start As System.DateTime = System.DateTime.Now
    Threading.Thread.Sleep(500)

    Dim Execution_End As System.DateTime = System.DateTime.Now
    MsgBox(String.Format("H:{0} M:{1} S:{2} MS:{3}", _
    DateDiff(DateInterval.Hour, Execution_Start, Execution_End), _
    DateDiff(DateInterval.Minute, Execution_Start, Execution_End), _
    DateDiff(DateInterval.Second, Execution_Start, Execution_End), _
    DateDiff(DateInterval.Second, Execution_Start, Execution_End) * 60))

Can someone show me a better way to do this? Maybe with a TimeSpan?

The solution:

Dim Execution_Start As New Stopwatch
Execution_Start.Start()

Threading.Thread.Sleep(500)

MessageBox.Show("H:" & Execution_Start.Elapsed.Hours & vbNewLine & _
       "M:" & Execution_Start.Elapsed.Minutes & vbNewLine & _
       "S:" & Execution_Start.Elapsed.Seconds & vbNewLine & _
       "MS:" & Execution_Start.Elapsed.Milliseconds & vbNewLine, _
       "Code execution time", MessageBoxButtons.OK, MessageBoxIcon.Information)

A better way would be to use Stopwatch, instead of DateTime differences.

Stopwatch Class - Microsoft Docs

Provides a set of methods and properties that you can use to accurately measure elapsed time.

// create and start a Stopwatch instance
Stopwatch stopwatch = Stopwatch.StartNew(); 

// replace with your sample code:
System.Threading.Thread.Sleep(500);

stopwatch.Stop();
Console.WriteLine(stopwatch.ElapsedMilliseconds);