使用此：

  string  connString =  @  SERVER = example.com; DATABASE = db_beta; UID = db_demo; PASSWORD = a~Sz4x; 1）X（N;; 

如需了解更多信息，请参阅： 2.4.4.5字符串文字 [ ^ ]

试试这个：

  string  connString =  @  SERVER = example.com; DATABASE = db_beta; UID ='db_demo'; PASSWORD ='a~Sz4x; 1）X（N'; ; 

或者这个：

  string  connString =   SERVER = example.com +  ; + 
  DATABASE = db_beta; + 
  UID ='db_demo'; + 
  PASSWORD = 'A〜Sz4x; 1）X（N';跨度>; 

I am trying to connect to an Mysql database through c# web service
The password for the database is a~Sz4x;1)X(N The above password has ;(SPECIAL CHARACTER) in it which is a line terminator in c# it throws below error

Format of the initialization string does not conform to specification starting at index 70.

Any help will be appreciated.

Use this:

string connString = @"SERVER=example.com;DATABASE=db_beta;UID=db_demo;PASSWORD=a~Sz4x;1)X(N;";

For further information, please see: 2.4.4.5 String literals[^]

Try this :

string connString = @"SERVER=example.com;DATABASE=db_beta;UID='db_demo';PASSWORD='a~Sz4x;1)X(N';";

or this:

string connString = "SERVER=example.com" + ";" +
"DATABASE=db_beta;" +
"UID='db_demo';" +
"PASSWORD='a~Sz4x;1)X(N';";