问题:进度条不更新 - 窗口冻结，直到所有功能完成

使用线程来防止主循环冻结.
您的函数 - SomeFunction、SecondFunction - 也可能在 global 命名空间中.
然后你必须通过 self.pbar 作为参数，例如SomeFunction(pbar): ... f(self.pbar).

注意:
你看到一个 RuntimeError: main thread is not in main loop
如果.destroy()App() 窗口，而Thread 正在运行！

导入 tkinter 作为 tk进口螺纹类应用程序(tk.Tk):def __init__(self):super().__init__()btn = tk.Button(self, text='Run',命令=lambda :threading.Thread(target=self.Load).start())btn.grid(row=0, column=0)self.pbar = ttk.Progressbar(self,maximum=2 *(5 * 5), mode='确定')self.pbar.grid(row=1, column=0)def SomeFunction(self):对于范围内的 num(5):print('SomeFunction({})'.format(num))self.pbar['value'] += 5时间.睡眠(1)返回编号def SecondFunction(self):对于范围内的 num(5):print('SecondFunction({})'.format(num))self.pbar['value'] += 5时间.睡眠(1)返回编号def 加载(自己):数字 = 0对于 [self.SomeFunction, self.SecondFunction] 中的 f:数字 += f()print('数字是:{}'.format(number))如果 __name__ == "__main__":应用程序().主循环()

输出:

SomeFunction(0)一些函数(1)一些函数(2)一些函数(3)一些函数(4)第二功能(0)第二功能(1)第二功能(2)第二功能(3)第二功能(4)数字是:8

使用 Python 测试:3.5*)无法使用 Python 2.7 进行测试

When using the Tkinter .after method, the code continues passed without waiting for the callback to complete.

import tkinter as tk
import tkinter.ttk as ttk
import time
from datetime import datetime

global i
i = 0
global j
j = 0

def SomeFunction():
    global i
    for num in range(10):
        i+=1
        x = barVar.get()
        barVar.set(x+5)
        histrun_mainWindow.update()
        time.sleep(2)

def SecondFunction():
    global j
    for num in range(10):
        j+=1
        x = barVar.get()
        barVar.set(x+5)
        histrun_mainWindow.update()
        time.sleep(2)

def Load(run_date):
    histrun_mainWindow.after(50, SomeFunction)
    histrun_mainWindow.after(50, SecondFunction)
    global i, j 
    print 'Number is :', i + j

histrun_mainWindow = tk.Tk()
run_date = datetime.today().date()
barVar = tk.DoubleVar()
barVar.set(0)
bar = ttk.Progressbar(histrun_mainWindow, length=200, style='black.Horizontal.TProgressbar', variable=barVar, mode='determinate')
bar.grid(row=1, column=0)
button= tk.Button(histrun_mainWindow, text='Run for this date ' + str(run_date), command=lambda:Load(run_date))
button.grid(row=0, column=0)
histrun_mainWindow.mainloop()

This example shows what is happening. The .after() calls the Load() function but doesn't wait for Load() to complete, it goes straight on to the next line.

I want i to print as 10 but because the .after() doesn't wait for Load() to finish it's additions, i prints as 0

The progress bar continues to update so I know that Load was called as it continues in the background after i is printed

Question: the progress bar doesn't update - the window freezes until all functions have completed

Use a Thread to prevent main loop from freezing.
Your functions - SomeFunction, SecondFunction - may also in global namespace.
Then you have to pass self.pbar as paramter, e.g. SomeFunction(pbar): ... f(self.pbar).

---

Note:
You see a RuntimeError: main thread is not in main loop
if you .destroy() the App() window while the Thread is running!

import tkinter as tk
import threading

class App(tk.Tk):
    def __init__(self):
        super().__init__()
        btn = tk.Button(self, text='Run', 
                              command=lambda :threading.Thread(target=self.Load).start())
        btn.grid(row=0, column=0)
        self.pbar = ttk.Progressbar(self, maximum=2 *(5 * 5), mode='determinate')
        self.pbar.grid(row=1, column=0)

    def SomeFunction(self):
        for num in range(5):
            print('SomeFunction({})'.format(num))
            self.pbar['value'] += 5
            time.sleep(1)
        return num

    def SecondFunction(self):
        for num in range(5):
            print('SecondFunction({})'.format(num))
            self.pbar['value'] += 5
            time.sleep(1)
        return num

    def Load(self):
        number = 0
        for f in [self.SomeFunction, self.SecondFunction]:
            number += f()
        print('Number is :{}'.format(number))

if __name__ == "__main__":
    App().mainloop()

Output:

SomeFunction(0)
SomeFunction(1)
SomeFunction(2)
SomeFunction(3)
SomeFunction(4)   
SecondFunction(0)
SecondFunction(1)
SecondFunction(2)
SecondFunction(3)
SecondFunction(4)
Number is :8

Tested with Python: 3.5 *)Could not test with Python 2.7