试试这个正则表达式在 eclipse/sed/你最喜欢的支持正则表达式的编辑器中搜索替换.

/**(?s:(?!*/).)**/

• ?s 将输入视为单行
• 一个起始字符串**
• 零个或多个
  • */的负前瞻
  • 空格或非空格字符
• 尾随字符串*/

编辑

要解决字符串包含 javadoc 的情况，请使用此正则表达式

((?<!\)"([^"]|(?<=\)")*")|(/**(?s:(?!*/).)**/)

并用第一个捕获组替换它

/1

那么如果你说这不应该匹配

///** */

或更复杂的情况

我建议，使用像 antlr 这样的解析器工具来使用

/**(?:(?!*/).)**/

Debuggex 演示

Is there any tool / Eclipse plugin that can remove all JavaDoc comments in a file?

The normal (non-JavaDoc) comments should be intact after running the tool.

Try this regex to search replace either in eclipse / sed / your favorite editor that has regex support.

/**(?s:(?!*/).)**/

• ?s treat input as single line
• a starting string **
• zero or more
  • negative lookahead for */
  • space or non space char
• a trailing string */

Edit

To tackle cases where strings containing javadoc, use this regex

((?<!\)"([^"]|(?<=\)")*")|(/**(?s:(?!*/).)**/)

and replace it with first capture group

/1

Then if you say this shouldn't match

///** */

or more complex cases

I suggest, using a parser tool like antlr to parse using java grammar for tokens like comments and strings and remove elements that you don't want

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Sometime I find my own regex answers cryptic !!

So here is some visual feedback

((?!\)"([^"]|(?=\)")*")|(/**(?:(?!*/).)**/)

Debuggex Demo

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/**(?:(?!*/).)**/

Debuggex Demo