在C ++中，只包含纯虚拟方法的类表示一个接口。 / p>

示例：

  //定义Serializable接口。 
 class Serializable {
 //如果对象可能是虚拟析构函数
 //通过指向可序列化的指针来删除
 virtual〜Serializable（）{} 

 virtual std :: string serialize（）const = 0; 
}; 

 //实现Serializable接口
 class MyClass：public MyBaseClass，public virtual Serializable {
 virtual std :: string serialize（）const {
 //实现去这里。 
} 
}; 
 

Possible Duplicate:
How do you declare an interface in C++?
Interface as in java in c++?

I am a Java programmer learning C++, and I was wondering if there is something like Java interfaces in C++, i.e. classes that another class can implement/extend more than one of. Thanks. p.s. New here so tell me if I did anything wrong.

In C++ a class containing only pure virtual methods denotes an interface.

Example:

// Define the Serializable interface.
class Serializable {
     // virtual destructor is required if the object may
     // be deleted through a pointer to Serializable
    virtual ~Serializable() {}

    virtual std::string serialize() const = 0;
};

// Implements the Serializable interface
class MyClass : public MyBaseClass, public virtual Serializable {
    virtual std::string serialize() const { 
        // Implementation goes here.
    }
};