没有ajax？好的，

var img = new Image();
img.src = "script.php?myVal=" + encodeURIComponent(theValueToPass);

浏览器会尝试通过请求网址加载图片。显然这将是一个愚蠢的差事，但你的PHP脚本将被执行，并在php的 $ _ GET ['myVal']

The browser will try to load the image by requesting the url. Obviously it will be a fools errand, but your php script will get executed and the value available in php's $_GET['myVal']