更新时间:2022-11-11 10:12:06
您应该将返回值存储在一个变量中:
You should simply store the return value in a variable:
$deliveryPrice = getDeliveryPrice(12);
echo $deliveryPrice; // will print 20
$ deliveryPrice
上面的变量是函数内部的不同的变量,而不是 $ deliveryPrice
。由于变量范围,后者在函数外部不可见。
The $deliveryPrice
variable above is a different variable than the $deliveryPrice
inside the function. The latter is not visible outside the function because of variable scope.