更新时间:2022-11-11 12:09:01
类Array
高清CONTAINS_ALL?其他
其他= other.dup
每个{| E |若i = other.index(E),然后other.delete_at(我)结束}
other.empty?
结束
结束
I need to tell if an array contains all of the elements of another array with duplicates.
[1,2,3].contains_all? [1,2] #=> true
[1,2,3].contains_all? [1,2,2] #=> false (this is where (a1-a2).empty? fails)
[2,1,2,3].contains_all? [1,2,2] #=> true
So the first array must contain as many or equal of the number of each unique element in the second array.
This question answers it for those using an array as a set, but I need to control for duplicates.
On Ruby 1.9.3p194
def bench
puts Benchmark.measure {
10000.times do
[1,2,3].contains_all? [1,2]
[1,2,3].contains_all? [1,2,2]
[2,1,2,3].contains_all? [1,2,2]
end
}
end
Results in:
Rohit 0.100000 0.000000 0.100000 ( 0.104486)
Chris 0.040000 0.000000 0.040000 ( 0.040178)
Sergio 0.160000 0.020000 0.180000 ( 0.173940)
sawa 0.030000 0.000000 0.030000 ( 0.032393)
@a1 = (1..10000).to_a
@a2 = (1..1000).to_a
@a3 = (1..2000).to_a
def bench
puts Benchmark.measure {
1000.times do
@a1.contains_all? @a2
@a1.contains_all? @a3
@a3.contains_all? @a2
end
}
end
Results in:
Rohit 9.750000 0.410000 10.160000 ( 10.158182)
Chris 10.250000 0.180000 10.430000 ( 10.433797)
Sergio 14.570000 0.070000 14.640000 ( 14.637870)
sawa 3.460000 0.020000 3.480000 ( 3.475513)
class Array
def contains_all? other
other = other.dup
each{|e| if i = other.index(e) then other.delete_at(i) end}
other.empty?
end
end