更新时间:2022-11-23 15:38:09
INT sum3darray(一[] [] [],大小);
应
INT sum3darray(INT A [] [3] [3],诠释大小);
或
INT sum3darray(INT(*一)[3] [3],诠释大小);
正如刚才@CoolGuy,你可以省略原型的参数的名称:
INT sum3darray(INT(*一)[3] [3],诠释大小);
可以写成
INT sum3darray(INT(*)[3] [3],INT);
另一种方式来处理多维数组(如果你不知道事先尺寸)正在使用VLA的(谢谢你米Oehm)或手动压平的数组,的看看。
Im trying to write a function that sums the elements of a 3d array, however it keeps saying there is a problem with the lines where I pass the 3d array as a parameter. My code is as follows:
#include <stdio.h>
int sum3darray(a[][][], size);
main() {
int check[3][3][3]={ 0 };
int size=3;
printf("The sum is %d\n",sum3darray(check,size));
}
int sum3darray(a[][][],size) {
int i,j,k,sum=0;
for(i=0;i<size;i++) {
for(j=0;j<size;j++) {
for(k=0;k<size;k++) {
printf("i=%d, j=%d,k=%d, checkijk=%d ",i,j,k,check[i][j][k]);
sum+=check[i][j][k];
printf("sum=%d\n", sum);
}
}
}
return(sum);
}
The compiler flags lines 3 and 11 as problems. Can anyone help?
int sum3darray(a[][][], size);
should be
int sum3darray(int a[][3][3], int size);
or
int sum3darray(int (*a)[3][3], int size);
As pointed out by @CoolGuy, you can omit the name of the parameters in prototypes:
int sum3darray(int (*a)[3][3], int size);
can be written as
int sum3darray(int (*)[3][3], int);
Another way to deal with multidimensional arrays (if you don't know the sizes beforehand) is using VLA's (thank you M Oehm) or flattening the array manually, take a look.