您对@PathParam的使用不正确。它不符合javadoc中记录的这些要求此处。我相信你只想发布JSON实体。您可以在资源方法中修复此问题以接受JSON实体。

Your use of @PathParam is incorrect. It does not follow these requirements as documented in the javadoc here. I believe you just want to POST the JSON entity. You can fix this in your resource method to accept JSON entity.

@Path("/hello")
public class Hello {

  @POST
  @Produces(MediaType.APPLICATION_JSON)
  @Consumes(MediaType.APPLICATION_JSON)
  public JSONObject sayPlainTextHello(JSONObject inputJsonObj) throws Exception {

    String input = (String) inputJsonObj.get("input");
    String output = "The input you sent is :" + input;
    JSONObject outputJsonObj = new JSONObject();
    outputJsonObj.put("output", output);

    return outputJsonObj;
  }
}

而且，您的客户端代码应如下所示：

And, your client code should look like this:

  ClientConfig config = new DefaultClientConfig();
  Client client = Client.create(config);
  client.addFilter(new LoggingFilter());
  WebResource service = client.resource(getBaseURI());
  JSONObject inputJsonObj = new JSONObject();
  inputJsonObj.put("input", "Value");
  System.out.println(service.path("rest").path("hello").accept(MediaType.APPLICATION_JSON).post(JSONObject.class, inputJsonObj));