为避免从< whatever>重复 import * 25次，你需要一个循环，例如：

To avoid repeating from <whatever> import * 25 times, you need a loop, such as:

import sys

def _allimports(modnames)
  thismod = sys.modules[__name__]

  for modname in modnames:
    submodname = '%s.%s' % (thismod, modname)
    __import__(submodname)
    submod = sys.modules[submodname]
    thismod.__dict__.update(submod.__dict__)

_allimports('a b c d e'.split())  # or whatever

我将有意义的代码放在函数中因为（ a）总是***[[为了性能并避免污染模块的命名空间]]，（b）在这种特殊情况下它也避免了事故（例如，某些子模块可能定义名称 thismod 或 modnames ...因此，将我们在循环中使用的名称保留在函数的本地，不是模块非常重要全局，所以他们不会被意外践踏; - ）。

I'm putting the meaningful code in a function because (a) it's always best [[for performance and to avoid polluting the module's namespace]], (b) in this particular case it also avoids accidents (e.g., some submodule might define a name thismod or modnames... so it's important to keep those names that we're using in the loop local to the function, not module globals, so they can't be accidentally trampled;-).

如果你想强制执行这个事实在名为 modname 的模块中，只有一个具有相同名称的类（或其他全局），将循环的最后一个语句更改为：

If you want to enforce the fact that a module named modname only has one class (or other global) with the same name, change the last statement of the loop to:

    setattr(thismod, modname, getattr(submod, modname))