更新时间:2022-12-09 17:12:19
这里的这一行 d = w[L]/v[L];
发生在几个步骤中
This line here d = w[L] /v[L];
takes place over several steps
d = (int)w[L] / (int)v[L]
d=(int)(w[L]/v[L]) //the integer result is calculated
d=(double)(int)(w[L]/v[L]) //the integer result is cast to double
换句话说,在你转换成双精度之前,精度已经消失了,你需要先转换成双精度,所以
In other words the precision is already gone before you cast to double, you need to cast to double first, so
d = ((double)w[L]) / (int)v[L];
这会强制 java 在整个过程中使用双精度数学,而不是使用整数数学,然后在最后强制转换为双精度
This forces java to use double maths the whole way through rather than use integer maths and then cast to double at the end