你必须在 spark 中使用 udf(用户定义函数)

from pyspark.sql.functions import udf示例_udf = udf(示例, LongType())df.withColumn('result', example_udf(df.address1, df.address2))

Let's say I have a data frame which looks like this:

+---+-----------+-----------+
| id|   address1|   address2|
+---+-----------+-----------+
|  1|address 1.1|address 1.2|
|  2|address 2.1|address 2.2|
+---+-----------+-----------+

I would like to apply a custom function directly to the strings in the address1 and address2 columns, for example:

def example(string1, string2):
    name_1 = string1.lower().split(' ')
    name_2 = string2.lower().split(' ')
    intersection_count = len(set(name_1) & set(name_2))

    return intersection_count

I want to store the result in a new column, so that my final data frame would look like:

+---+-----------+-----------+------+
| id|   address1|   address2|result|
+---+-----------+-----------+------+
|  1|address 1.1|address 1.2|     2|
|  2|address 2.1|address 2.2|     7|
+---+-----------+-----------+------+

I've tried to execute it in a way I once applied a built-in function to the whole column, but I got an error:

>>> df.withColumn('result', example(df.address1, df.address2))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 2, in example
TypeError: 'Column' object is not callable

What am I doing wrong and how I can apply a custom function to strings in selected columns?

You have to use udf (user defined function) in spark

from pyspark.sql.functions import udf
example_udf = udf(example, LongType())
df.withColumn('result', example_udf(df.address1, df.address2))