请记住，默认情况下，杰克逊从getter或setter(第一个匹配的)中确定属性名称.

Remember that Jackson, by default, determines the property name from either the getter or setter (the first that matches).

要反序列化POJOUserDetails类型的对象，Jackson将查找三个属性

To deserialize an object of type POJOUserDetails, Jackson will look for three properties

public void setFirstName(String firstName) {

public void setLastName(String lastName) {

public void setActive(boolean isActive) {

JSON中的

.这些基本上是firstName，lastName，active.

in the JSON. These are basically firstName, lastName, active.

您将获得以下JSON

You get the following JSON

{ "firstName": "Test", "lastName": "1", "isActive": 1 }

因此，已映射firstName和lastName，但是您没有名为isActive的属性.

So firstName and lastName are mapped, but you don't have a property named isActive.

Jackson依赖于Java Bean的命名约定及其访问器(获取器)和更改器(设置器).对于类似

Jackson depends on Java Bean naming conventions with their accessors (getters) and mutators (setters). For a field like

private boolean isActive;

适当的setter/getter名称是

the appropriate setter/getter names are

public boolean getIsActive() {
    return isActive;
}

public void setIsActive(boolean isActive) {
    this.isActive = isActive;
}

因此，您有两种可能的解决方案.如上所示更改您的getter/setter或使用@JsonProperty注释字段，以便Jackson使用字段名称来确定属性名称

So you have two possible solutions. Change your getter/setter as shown above or annotate your field with @JsonProperty so that Jackson uses the field name to determine the property name

@JsonProperty
private boolean isActive;