您可以使用正则表达式（（[[^（] *？（\（。*？\））？）*）（，| $）匹配：

You can use the regular expression (([^(]*?(\(.*?\))?)*)(,|$) to match:

• [^（] *？零个或多个（但应尽可能少）非开括号字符


• （\（。*？\））？然后，可选地，使用一个大括号和尽可能少的字符，直到大括号为止。


• （）* 包裹在一个捕获组中，重复零次或多次


• （）包裹在捕获组中，以便能够引用整个匹配项


• （，| $）后跟逗号或字符串结尾。

• [^(]*? Zero-or-more (but as few as possible) non-opening-bracket characters
• (\(.*?\))? Then, optionally, an opening bracket and as few characters as possible until the closing bracket.
• ( )* Wrapped in a capturing group repeated zero-or-more times
• ( ) Wrapped in a capturing group to be able to reference the entire matched item
• (,|$) Followed by either a comma or the end-of-string.

就像这样：

SQL提琴

Oracle 11g R2架构设置：

CREATE TABLE table_name ( ID, Kategory ) AS
SELECT 1, 'ATD 5(2830),ATO 4(510),EDI 1,EH A1,SCI 2,SS 1,STO-SE 1(oral, CNS, blood),STO-SE 2(oral, respiratory effects)' FROM DUAL;

查询1 ：

SELECT ID,
       l.COLUMN_VALUE AS item,
       REGEXP_SUBSTR(
         Kategory,
         '(([^(]*?(\(.*?\))?)*)(,|$)',
         1,
         l.COLUMN_VALUE,
         NULL,
         1
       ) AS value
FROM   table_name t
       CROSS JOIN
       TABLE(
         CAST(
           MULTISET(
             SELECT LEVEL
             FROM   DUAL
             CONNECT BY LEVEL < REGEXP_COUNT( t.Kategory, '(([^(]*?(\(.*?\))?)*)(,|$)' )
           )
           AS SYS.ODCINUMBERLIST
         )
       ) l

结果 ：

Results:

| ID | ITEM |                               VALUE |
|----|------|-------------------------------------|
|  1 |    1 |                         ATD 5(2830) |
|  1 |    2 |                          ATO 4(510) |
|  1 |    3 |                               EDI 1 |
|  1 |    4 |                               EH A1 |
|  1 |    5 |                               SCI 2 |
|  1 |    6 |                                SS 1 |
|  1 |    7 |          STO-SE 1(oral, CNS, blood) |
|  1 |    8 | STO-SE 2(oral, respiratory effects) |