一种解决方法是使用正则表达式.假设有什么输入，您可以做类似的事情

One way to approach this would be with the use of regular expressions. Assuming whatever input, you can do something like

 var expression = /(https?:\/\/(?:www\.|(?!www))[^\s\.]+\.[^\s]{2,}|www\.[^\s]+\.[^\s]{2,})/gi;
 var matches = input.match(expression);

然后，您可以使用 indexOf

for(match in matches)
    {
        var result = {};
        result['link'] = matches[match];
        result['startsAt'] = input.indexOf(matches[match]);
        result['endsAt'] = 
            input.indexOf(matches[match]) + matches[match].length;
     }

当然，您可能必须修改正则表达式本身才能满足您的特定需求.

Of course, you may have to tinker with the regular expression itself to suit your specific needs.

您可以在此小提琴