更新时间:2023-02-23 11:22:01
除非定义了变量 k
,否则这可能是导致您遇到麻烦的原因.像这样的事情会做你想做的:
Unless the variable k
is defined, that's probably what's causing your trouble. Something like this will do what you want:
var new_tweets = { };
new_tweets.k = { };
new_tweets.k.tweet_id = 98745521;
new_tweets.k.user_id = 54875;
new_tweets.k.data = { };
new_tweets.k.data.in_reply_to_screen_name = 'other_user';
new_tweets.k.data.text = 'tweet text';
// Will create the JSON string you're looking for.
var json = JSON.stringify(new_tweets);
您也可以一次性完成:
var new_tweets = {
k: {
tweet_id: 98745521,
user_id: 54875,
data: {
in_reply_to_screen_name: 'other_user',
text: 'tweet_text'
}
}
}