您可以使用此

You can use this function that take 2 parameters: the param you are trying to remove and your source URL:

function removeParam(key, sourceURL) {
    var rtn = sourceURL.split("?")[0],
        param,
        params_arr = [],
        queryString = (sourceURL.indexOf("?") !== -1) ? sourceURL.split("?")[1] : "";
    if (queryString !== "") {
        params_arr = queryString.split("&");
        for (var i = params_arr.length - 1; i >= 0; i -= 1) {
            param = params_arr[i].split("=")[0];
            if (param === key) {
                params_arr.splice(i, 1);
            }
        }
        rtn = rtn + "?" + params_arr.join("&");
    }
    return rtn;
}

var url = "at merge ?derivate=21&gear_type__in=13&engine=73&month=05&year=2017";

var url2 = removeParam("month", url);
var url3 = removeParam("year", url2);

console.log(url3);

带有正则表达式的替代解决方案