仍然适用于NumPy数组的非NumPy解决方案是使用 OrderedCounter ，后跟 sorted 和自定义功能:

A non-NumPy solution, which does still work with NumPy arrays, is to use an OrderedCounter followed by sorted with a custom function:

from collections import OrderedDict, Counter

class OrderedCounter(Counter, OrderedDict):
    pass

L = [3,4,5,1,2,4,1,1,2,4]

c = OrderedCounter(L)
keys = list(c)

res = sorted(c, key=lambda x: (-c[x], keys.index(x)))

print(res)

[4, 1, 2, 3, 5]