更新时间:2022-10-03 13:53:26
205. Isomorphic Strings 字符串相似
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
题目大意:
判断两个字符串是否相似。
思路:
使用双map来进行比较。map键为字符串元素,值为字符上一次出现的位置。
代码如下:
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class Solution {
public :
bool isIsomorphic(string s, string t) {
if (s.size() != t.size())
return false ;
unordered_map< char , int > maps;
unordered_map< char , int > mapt;
for ( int i = 0;i < s.size();i++)
{
if (maps.find(s[i]) == maps.end() && mapt.find(t[i]) == mapt.end())
{
maps.insert(pair< char , int >(s[i],i));
mapt.insert(pair< char , int >(t[i],i));
}
else if (maps.find(s[i]) != maps.end() && mapt.find(t[i]) != mapt.end())
{
if (maps[s[i]] != mapt[t[i]])
return false ;
else
{
maps[s[i]] = i;
mapt[t[i]] = i;
}
}
else
return false ;
}
return true ;
}
};
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