更新时间:2022-11-18 21:38:09
您需要在查询字符串中传递数量,例如:
?post_type = product& add-to-cart = 100& quantity = 2
我已经修改了您的代码
< script>jQuery('#buy').click(function(e){e.preventDefault();var myStringArray = [<?php echo $ p_id;?>];var arrayLength = myStringArray.length;for(var i = 0; i< arrayLength; i ++){addToCart(myStringArray [i],2);}返回true;//window.location.href ="http://seoexpertiser.ca/glassful/cart/";});函数addToCart(p_id,qu){$ .get('/glassful/?post_type = product& add-to-cart ='+ p_id +'& quantity ='+ qu,function(){//成功$(.show_success").show();});}</script>
我认为这可以解决您的问题.
I want to create custom add to cart button to add my 3 product into cart with 2 quantity for each..
For add three product into cart I have done using like this:
<a id="buy" class="single_add_to_cart_button shop-skin-btn shop-flat-btn alt" href="#">ADD MY PRODUCT</a>
$p_id = my product id eg: 45,99,152
<script>
jQuery('#buy').click(function(e) {
e.preventDefault();
var myStringArray = [<?php echo $p_id; ?>];
var arrayLength = myStringArray.length;
for (var i = 0; i < arrayLength; i++) {
addToCart(myStringArray[i]);
}
return true;
});
function addToCart(p_id) {
$.get('/glassful/?post_type=product&add-to-cart=' + p_id, function() {
$(".show_success").show();
});
}
</script>
It will add my resulted product into cart but with only 1 quantity Please let me know how I can add quantity? I want to add 2 quantity of each product.
Mean when click on add to cart three product will added to cart with 2 quantity each.
Thanks for help in advance..
You need to pass quantity in query string like:
?post_type=product&add-to-cart=100&quantity=2
I have modify you code
<script>
jQuery('#buy').click(function(e) {
e.preventDefault();
var myStringArray = [<?php echo $p_id; ?>];
var arrayLength = myStringArray.length;
for (var i = 0; i < arrayLength; i++) {
addToCart(myStringArray[i],2);
}
return true;
//window.location.href = "http://seoexpertiser.ca/glassful/cart/";
});
function addToCart(p_id,qu) {
$.get('/glassful/?post_type=product&add-to-cart=' + p_id +'&quantity='+qu, function() {
// success
$(".show_success").show();
});
}
</script>
I think this will solve your problem.