由于使用的是SQL Server，因此可以使用PIVOT函数.

Since you are using SQL Server, then you can use the PIVOT function.

如果您的值已知，则可以对值进行硬编码:

If your values are known, then you can hard-code the values:

select *
from
(
  select id, value, date
  from yourtable
) src
pivot
(
  max(value)
  for date in ([2012-12-29], [2012-10-29], [2013-02-02])
) piv

请参见带演示的SQL提琴.

但是，如果它们未知，那么您将需要使用动态sql:

But if they are unknown, then you will need to use dynamic sql:

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT distinct ',' + QUOTENAME(convert(varchar(50), date, 120)) 
                    from yourtable
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT id, ' + @cols + ' from 
             (
                select id, value, convert(varchar(50), date, 120) date
                from yourtable
            ) x
            pivot 
            (
                max(value)
                for date in (' + @cols + ')
            ) p '

execute(@query)

请参见带演示的SQL提琴.

这两个查询的结果是:

| ID | 2012-10-29 00:00:00 | 2012-12-29 00:00:00 | 2013-02-02 00:00:00 |
------------------------------------------------------------------------
|  1 |                  54 |                  55 |                  89 |
|  2 |                  54 |                  45 |              (null) |
|  4 |                  90 |                  78 |              (null) |