将其转换为浮动然后执行：

cast it to float and then do it:

int i = 56472201;

float j = ((float) i)/1000000.0

编辑：由于精度（在您的情况下需要），请使用double。同样如Konrad Rudolph指出的那样，不需要显式投射：

Due to precision(needed in your case), use double. Also as pointed by Konrad Rudolph, no need for explicit casting:

double j = i / 1000000.0;